0=-16t^2+2304

Solution for 0=-16t^2+2304 equation:

0=-16t^2+2304

We move all terms to the left:

0-(-16t^2+2304)=0

We add all the numbers together, and all the variables

-(-16t^2+2304)=0

We get rid of parentheses

16t^2-2304=0

a = 16; b = 0; c = -2304;
Δ = b2-4ac
Δ = 02-4·16·(-2304)
Δ = 147456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{147456}=384$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-384}{2*16}=\frac{-384}{32}
=-12
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+384}{2*16}=\frac{384}{32}
=12
$